利用XOR对字符串进行加密的函数

'使用方法:
'tmp = stringendecn("中华人民共和国", 75)
'如果要解密的话，只须键入以下语句：
'tmp1 = StringEnDeCodecn(tmp, 75)

Private Function StringEnDeCodecn(strSource As String, MA) As String
On Error GoTo ErrEnDeCode
Dim X As Single
Dim CHARNUM As Long, RANDOMINTEGER As Integer
Dim SINGLECHAR As String * 1
Dim strTmp As String
If MA < 0 Then
MA = MA * (-1)
End If
X = Rnd(-MA)
For i = 1 To Len(strSource) Step 1 '取单字节内容
SINGLECHAR = Mid(strSource, i, 1)
CHARNUM = Asc(SINGLECHAR)
g: RANDOMINTEGER = Int(127 * Rnd)
If RANDOMINTEGER < 30 Or RANDOMINTEGER > 100 Then GoTo g
CHARNUM = CHARNUM Xor RANDOMINTEGER
strTmp = strTmp & Chr(CHARNUM)
Next i
StringEnDeCodecn = strTmp
Exit Function
ErrEnDeCode:
StringEnDeCodecn = ""
MsgBox Err.Number & "\" & Err.Description
End Function